Remark: The immediate application of the equations (8) and (9) in the boxed prescription on page 520 leads to a solution in the form (8) where \[ a_0 = 1, \quad a_n=\frac{2}{n\pi} \sin \frac{n\pi}{2}, \quad n=1,2,\ldots. \] The form presented in the book's answer is obtained by noting that the values of $\sin \frac{n\pi}{2}$ cycle through $1, 0, -1, 0$, making every other term in the series zero.
Furthermore, in the book's answers to exercises 11–14, the $\alpha$ is missing in the exponents.
Back to the table of contents | Author: Rouben Rostamian |