(Spotted by Kevin Stern) In that same fraction, the $+bdi^2$ in the numerator should be $-bdi^2$. As a result, the $ac-bd$ in the final result of equation (5) should be $ac+bd$. In summary, equation (5)'s final form is \[ =\Big( \frac{ac+bd}{c^2+d^2}\Big) +\Big( \frac{bc-ad}{c^2+d^2}\Big)\,i \]
Back to the table of contents | Author: Rouben Rostamian |