Final Exam
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Let $\vec{x}(u,v)$ be a parametrization of a surface and suppose that $E=1$,
$F=0$, and $G$ is some function of $u$ and $v$. Find the surface's
Gaussian curvature, $K$, in terms of $G$.
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A parametrization $\vec{x}(u,v)$ of a surface such that $E=G=1$ is called a
Tchebycheff parametrization. It follows that
$\vec{x}_u$ and $\vec{x}_v$ are unit vectors, and therefore
$F = \vec{x}_u \cdot \vec{x}_v = \cos\theta$, where $\theta$
is the angle between those vectors.
Find the surface's Gaussian curvature $K$ in terms of $\theta$.
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Consider the spacecurve $\vec{\alpha}(s)$ parameterized by arclength,
and let $\vec{b}(s)$ be its binormal vector.
Define the ruled surface $S$ through
$\vec{x}(s,v) = \vec{\alpha}(s) + v\,\vec{b}(s)$.
Show that $\vec{\alpha}$ is a geodesic on $S$.
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Let $R$ be the part of the graph of the paraboloid
$z=x^2+y^2$ in Cartesian coordinates
$x, y, z$ that lies between the planes $z=0$
and $z=a^2$ for some $a>0$. For convenience, let's express
$R$ in the familiar parametric form
$\vec{x}(u,v) = \langle u, v, u^2 + v^2 \rangle$
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Calculate the Gaussian curvature $K$ of $R$
as a function $u$ and $v$.
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Evaluate $\ds\int_R K \,dA$.
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Evaluate $\ds\int_C \kappa_g \,ds$,
where $\kappa_g$ is the geodesic curvature of $R$'s
boundry curve $C$.
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Conclude that the Gauss–Bonnet theorem holds on $R$.
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In the subfigure (a) below, the angle $\theta$ is
$15^\circ = \frac{\pi}{12}$ radians. The slanted line
is rotated about the $z$ axis to generate the right circular
cone of base radius $1$ and height $h$, shown in subfigure (b).
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Find the parametrization $\vec{x}(u,v)$ of the cone, where
$u \in [-\pi,\pi]$ and $v \in [0,h]$.
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Calculate and plot the geodesic
$\vec{\alpha}(t) = \vec{x}\bigl( u(t), v(t) \bigr)$
that takes off from $\vec{x}(0,1)$ with
$u'(0)=v'(0)=1$ as seen in subfigure (b),
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(a) |
(b) |