simeq_newton.c running 
check residual F1(2,3)=0  0 
check residual F2(2,3)=0  0 
J at 2,3 = 
MAT[0,0] = 20.000000 
MAT[0,1] = 6.000000 
MAT[1,0] = 5.000000 
MAT[1,1] = 4.000000 
F1P1 numeric = 20.3 
F2P1 numeric = 6.1 
F1P2 numeric = 5 
F2P2 numeric = 4 
JI at 2,3 = 
MAT[0,0] = 0.080000 
MAT[0,1] = -0.120000 
MAT[1,0] = -0.100000 
MAT[1,1] = 0.400000 
M = identity 
MAT[0,0] = 1.000000 
MAT[0,1] = -0.000000 
MAT[1,0] = 0.000000 
MAT[1,1] = 1.000000 
X = 
VEC[0] = 1.000000 
VEC[1] = 1.000000 
residuals = 
VEC[0] = -23.000000 
VEC[1] = -11.000000 
J = 
MAT[0,0] = 10.000000 
MAT[0,1] = 2.000000 
MAT[1,0] = 3.000000 
MAT[1,1] = 3.000000 
JI transpose = 
MAT[0,0] = 0.125000 
MAT[0,1] = -0.125000 
MAT[1,0] = -0.083333 
MAT[1,1] = 0.416667 
T = J^-1 * F = 
VEC[0] = -1.500000 
VEC[1] = -2.666667 
Xn = 
VEC[0] = 2.500000 
VEC[1] = 3.666667 
residuals = 
VEC[0] = 14.750000 
VEC[1] = 6.250000 
T = 
VEC[0] = -0.950787 
VEC[1] = 4.897638 
Xn = 
VEC[0] = 3.450787 
VEC[1] = -1.230971 
residuals = 
VEC[0] = 1.898765 
VEC[1] = -12.252616 
T = 
VEC[0] = -1.113785 
VEC[1] = 1.302713 
Xn = 
VEC[0] = 4.564572 
VEC[1] = -2.533684 
residuals = 
VEC[0] = 14.971046 
VEC[1] = -14.361807 
T = 
VEC[0] = -2.388214 
VEC[1] = 4.316230 
Xn = 
VEC[0] = 6.952786 
VEC[1] = -6.849914 
residuals = 
VEC[0] = 25.827390 
VEC[1] = -33.937368 
T = 
VEC[0] = -3.859468 
VEC[1] = 5.495386 
Xn = 
VEC[0] = 10.812255 
VEC[1] = -12.345300 
residuals = 
VEC[0] = 62.032713 
VEC[1] = -66.078529 
T = 
VEC[0] = -6.371525 
VEC[1] = 8.958915 
Xn = 
VEC[0] = 17.183780 
VEC[1] = -21.304215 
residuals = 
VEC[0] = 135.736332 
VEC[1] = -144.596864 
T = 
VEC[0] = -9.808772 
VEC[1] = 13.243632 
Xn = 
VEC[0] = 26.992552 
VEC[1] = -34.547847 
residuals = 
VEC[0] = 309.161671 
VEC[1] = -314.024959 
T = 
VEC[0] = -15.032799 
VEC[1] = 20.223305 
Xn = 
VEC[0] = 42.025350 
VEC[1] = -54.771153 
residuals = 
VEC[0] = 693.115983 
VEC[1] = -701.214473 
T = 
VEC[0] = -22.674672 
VEC[1] = 30.308571 
Xn = 
VEC[0] = 64.700022 
VEC[1] = -85.079724 
residuals = 
VEC[0] = 1562.278882 
VEC[1] = -1567.426610 
T = 
VEC[0] = -34.146795 
VEC[1] = 45.600120 
Xn = 
VEC[0] = 98.846817 
VEC[1] = -130.679843 
residuals = 
VEC[0] = 3513.520476 
VEC[1] = -3520.799820 
T = 
VEC[0] = -51.278860 
VEC[1] = 68.407042 
Xn = 
VEC[0] = 150.125677 
VEC[1] = -199.086885 
simeq_newton finished